From 595e52bb5cad842045127d56a978bd59a98bd45b Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?Ciro=20Santilli=20=E5=85=AD=E5=9B=9B=E4=BA=8B=E4=BB=B6=20?=
 =?UTF-8?q?=E6=B3=95=E8=BD=AE=E5=8A=9F?= <ciro.santilli@gmail.com>
Date: Sun, 23 Sep 2018 19:03:14 +0100
Subject: [PATCH] run: try to overcome run BlockingIOError

---
 common.py | 7 ++++++-
 1 file changed, 6 insertions(+), 1 deletion(-)

diff --git a/common.py b/common.py
index 671bc9a..2c20e18 100644
--- a/common.py
+++ b/common.py
@@ -397,6 +397,7 @@ def run_cmd(
     # Ignoring the exception is not enough as it prints a warning anyways.
     #sigpipe_old = signal.getsignal(signal.SIGPIPE)
     #signal.signal(signal.SIGPIPE, signal.SIG_DFL)
+
     # https://stackoverflow.com/questions/15535240/python-popen-write-to-stdout-and-log-file-simultaneously/52090802#52090802
     with subprocess.Popen(cmd, stdout=stdout, stderr=stderr, env=env, **kwargs) as proc:
         if out_file is not None:
@@ -407,7 +408,11 @@ def run_cmd(
                     if byte:
                         if show_stdout:
                             sys.stdout.buffer.write(byte)
-                            sys.stdout.flush()
+                            try:
+                                sys.stdout.flush()
+                            except BlockingIOError:
+                                # TODO understand. Why, Python, why.
+                                pass
                         logfile.write(byte)
                     else:
                         break